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x^2-13x-14=7x-9
We move all terms to the left:
x^2-13x-14-(7x-9)=0
We get rid of parentheses
x^2-13x-7x+9-14=0
We add all the numbers together, and all the variables
x^2-20x-5=0
a = 1; b = -20; c = -5;
Δ = b2-4ac
Δ = -202-4·1·(-5)
Δ = 420
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{420}=\sqrt{4*105}=\sqrt{4}*\sqrt{105}=2\sqrt{105}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-2\sqrt{105}}{2*1}=\frac{20-2\sqrt{105}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+2\sqrt{105}}{2*1}=\frac{20+2\sqrt{105}}{2} $
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